What is the voltage drop on a single-phase, 208-volt branch circuit supplying a 130-ampere load at a distance of 185 feet with 2/0 AWG THWN aluminum conductors?

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Multiple Choice

What is the voltage drop on a single-phase, 208-volt branch circuit supplying a 130-ampere load at a distance of 185 feet with 2/0 AWG THWN aluminum conductors?

Explanation:
To determine the voltage drop in this scenario, you can use the voltage drop formula specific to single-phase circuits: Voltage Drop (V) = (2 × K × I × L) / 1000 Where: - K is the resistivity constant for the material (copper or aluminum). For aluminum conductors, K is approximately 12.9 ohms per mil foot. - I is the current in amperes (130 A). - L is the one-way distance in feet (185 ft). First, substitute the values into the formula. Since this is a single-phase circuit, the formula includes a factor of 2 to account for both the outgoing and return paths of the current: Voltage Drop = (2 × 12.9 × 130 × 185) / 1000 Calculating this gives: - 2 × 12.9 = 25.8 - 25.8 × 130 = 3354 - 3354 × 185 = 620490 Then, divide by 1000: 620490 / 1000 = 620.49 To convert this to volts of drop, calculate the voltage drop by putting it into context of the initial voltage. Finally

To determine the voltage drop in this scenario, you can use the voltage drop formula specific to single-phase circuits:

Voltage Drop (V) = (2 × K × I × L) / 1000

Where:

  • K is the resistivity constant for the material (copper or aluminum). For aluminum conductors, K is approximately 12.9 ohms per mil foot.

  • I is the current in amperes (130 A).

  • L is the one-way distance in feet (185 ft).

First, substitute the values into the formula. Since this is a single-phase circuit, the formula includes a factor of 2 to account for both the outgoing and return paths of the current:

Voltage Drop = (2 × 12.9 × 130 × 185) / 1000

Calculating this gives:

  • 2 × 12.9 = 25.8

  • 25.8 × 130 = 3354

  • 3354 × 185 = 620490

Then, divide by 1000:

620490 / 1000 = 620.49

To convert this to volts of drop, calculate the voltage drop by putting it into context of the initial voltage. Finally

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